Question

x-2y = 3, 3x – 3y = 5by elimination method
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Answer 1

x-2y=3

3x-3y=5

now

Multiply first equation by 3

we get

3x-6y=9

3x-3y=5

- + -

-3y=4

y=-4/3

x-2y=3

x-2×-4/3=3

x-8/3=3

x=3+8/3

lcm is 3

9+8/3

17/3

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Answer 2

x-2y=3---eqn(1)

3x-3y=5----eqn(2)

eqn(1)×3; 3x-6y=9 (3)

3x-3y=5

(-) (+) (-)

subtract eqn (3)and (2)

therefore we will be left with

-3y=4 ;;so y=-4÷3

Now;

x-2y=3

x-2(-4÷3)=3

x+8÷3=3

x=3-8÷3

x=1÷3

x=-4\3; y=1/3