(x + 2y+3)(x+2y+7) with formula
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(x+2y+3)(x+2y+7)
=[(x+2y)+3][(x+2y)+7] taking (x+2y) as 'a'
=(a+3)(a+7)
=a(a+7)+3(a+7)
=a^2+7a+3a+21
=a^2+10a+21
Now, putting the value of a in the eq.
=(x+2y)^2+10*(x+2y)+21
=x^2+2y^2+10x+20y+21
HOPE YOU FIND IT HELPFUL..
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hope this helps u stay happy and healthy ❤️
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