Question

(x-2y+3)(x2+4y2+2xy+6y-3x+9)

Answer 1

let's simplify your equations step by step

(x−2y+3)(x2+4y2+2xy+6y−3x+9)

=(x+−2y+3)(x2+4y2+2xy+6y+−3x+9)

=(x)(x2)+(x)(4y2)+(x)(2xy)+(x)(6y)+(x)(−3x)+(x)(9)+(−2y)(x2)+(−2y)(4y2)+(−2y)(2xy)+(−2y)(6y)+(−2y)(−3x)+(−2y)(9)+(3)(x2)+(3)(4y2)+(3)(2xy)+(3)(6y)+(3)(−3x)+(3)(9)

=x3+4xy2+2x2y+6xy−3x2+9x−2x2y−8y3−4xy2−12y2+6xy−18y+3x2+12y2+6xy+18y−9x+27

=x3−8y3+18xy+27

so your answer is x3 - 8y3 + 18xy + 27


thanks

Answer 2

Answer:

Step-by-step explanation: