Question

(x+2y) (-3x-y) -(x+y) (x-y) (x-y) +(x-2y) (-2x+y)
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Answer 1

Answer:

On simplifying we get:

-x³+x²y+xy²-y³-5x²-2xy-4y²

Answer 2

Answer:

$=-x^{3} -y^{3} -5x^{2} -4y^{2} +x^{2} y+xy^{2}-2xy$

Step-by-step explanation:

Given : $(x+2y)(-3x-y)-(x+y)(x-y)(x-y)+(x-2y)(-2x+y)$

To find : The product of this equation

Solution :

• The given equation is, ( $(x+2y)(-3x-y)-(x+y)(x-y)(x-y)+(x-2y)(-2x+y)$

• In order to find product of this equation, we have to solve the brackets first. we get

      $(x+2y)(-3x-y)-(x+y)(x-y)(x-y)+(x-2y)(-2x+y)$$= (-3x^{2} -xy-6xy-2y^{2} )-(x^{2} -y^{2} )(x-y)+(-2x^{2} +xy+4xy-2y^{2})$

= $(-3x^{2} -xy-6xy-2y^{2})-(x^{3}-x^{2} y-xy^{2}+y^{3} )-2x^{2} +xy+4xy-2y^{2}$

• Adding like terms, we get

$= -x^{3}-y^{3} -3x^{2} -2x^{2} -2y^{2}-2y^{2}+x^{2} y+xy^{2}-xy-6xy +xy+4xy$

$=-x^{3} -y^{3} -5x^{2} -4y^{2} +x^{2} y+xy^{2}-2xy$