X-2y+3z=2 , 2x-3y+z=1 , 3x-y+2z=9 find x y z
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Answer:
\left( \begin{array}{ccc} x\to \frac{38}{13} & y\to \frac{33}{13} & z\to \frac{18}{13} \end{array} \right)(
x→38/13
y→33/13
z→18/13
Step-by-step explanation:
solved through crammer's method.
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