(x + 2y + 3z)²=
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Topic
Algebraic Identities
To Solve
( x + 2y + 3z )²
Solution
Technique 1
Use multiplication method
( x + 2y + 3z )( x + 2y + 3z )
x( x +2y + 3z ) + 2y( x + 2y + 3z ) + 3z( x + 2y + 3z )
x² + 2xy + 3zx + 2xy + 4y² + 6yz + 3zx + 6zy + 9z²
x² + 4y² + 9z² + 3zx + 3zx + 2xy + 2xy + 6yz + 6yz
x² + 4y² + 9z² + 6xz + 4xy + 12yz
Technique 2
Use formula,
( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca
here
- a = x
- b = 2y
- c = 3z
Apply the formula,
( x + 2y + 3z )²
x² + (2y)² + (3z)² + 2(x)(2y) + 2(2y)(3z) + 2(3z)(x)
x² + 4y² + 9z² + 4xy + 12yz + 6xz
Answer
So, answer is,
x² + 4y² + 9z² + 4xy + 12yz + 6xz
which is option A.
akshaya5097:
Thanks for helping
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