Question

(x-2y+3z)². Please give me the ans fast .​

Answer 1

Question :

• To Expand (x-2y+3z)²

Solution :

We know that,

$\red\bigstar\:\boxed{\sf (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca}$

Applying this Identity here,

Putting ,

• a = x
• b = -2y
• c = 3z

$\large\purple{\underline{\mathfrak{Substituting\:the\: values}}} :$

$\sf \longmapsto (x -2y+3z)^2$

$\sf \implies x^2 + (-2y)^2 + (3z)^2 + 2(x)(-2y)+2(-2y)(3z)+2(3z)(x)$

⟹ x² + 4y² + 9z² + (-4xy) + (-12yz) + 6xz

⟹ x² + 4y² + 9z² -4xy -12yz + 6xz

━━ ━━ ━━ ━━━ ━━ ━━ ━━ ━━

More to know :

• (a-b)³ = a³ -b³ -3ab(a-b)

• (a+b)³ = a³ + b³ + 3ab(a+b)

• a³+b³ = (a +b)(a² + b² -2ab)

• a³- b³ = (a - b)(a² + b² +2ab)

• (a + b+c)² = a²+b²+c² + 2ab + 2bc+ 2ca