Question

(x+2y+3z)(x^2+4y^2+9z^2-2xy-6yz-3zx)​

Answer 1

Answer:

x³+8y³+27z³-18xyz

Explanation:

We know that, (x+y+z)(x  

2

+y  

2

+z  

2

−xy−yz−zx)=x  

3

+y  

3

+z  

3

−3xyz

∴(x+2y+3z)(x  

2

+4y  

2

+9z  

2

−2xy−6yz−3zx)

=(x+2y+3z)[x  

2

+(2y)  

2

+(3z)  

2

−(x)(2y)−(2y)(3z)−(3z)(x)]

=(x  

3

)+(2y)  

3

+(3z)  

3

−3(x)(2y)(3z)

=x  

3

+8y  

3

+27z  

3

−18xyz

Answer 2

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