Question

x+2y-4=0
2x+4y-12=0
solve this using substitution method...

Answer 1

the given system of equations van be rewritten as
x+2y=4 ........[1]
2x+4y=12........[2]

from [1] x=4-2y........ [3]

putting this value of x in [2] we get,

2[4-2y]+4y=12
8-4y-4y=12
8=12, which is a false statement.

so, the given system of equations will have no solution.

HOPE THIS HELPS!!!!

,PLEASE MARK IT AS BRAINLIEST........

Answer 2

Answer:

firstly

X+2y-4=0 can be written as

X+2y=4. eq. 1

and 2x+4y-12 can be written as

2x+4y=12. eq. 2

From 1st

x= 4-2y eq. 3

substituting eq 3 in eq. 2

2(4-2y)+4y=12

8-4y+4y=12

8-0=12

8≠12

therefore, the set of equation has no solution and

hence parallel to each other.

Thank you

Hope it helps