x + 2y = 4
2x +y =5 solve using matrix method
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Given system of linear equations are
2x+3y+3z=5
x−2y+z=−4
3x−y−2z=3.
Represent it in matrix form
⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤⎣⎢⎢⎡xyz⎦⎥⎥⎤=⎣⎢⎢⎡5−43⎦⎥⎥⎤ which is in the form of AX=B
A=⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤
∣A∣=10+15+15=40=0
∴ A−1 exists
To find adjoint of A
A
Hence, x=1,y=2 and z=−1
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