Math, asked by pragnya123456, 8 months ago

x-2y=4 xy=(-6) evaluate x^3-8y^3​

Answers

Answered by harshita663
0

Step-by-step explanation:

1.x-2y=4

2.xy=(-6)

then from 1st equation x=4+2y

now we put the value of x in the equation 2nd

(4+2y)y=(-6)

4y+2y^2=(-6)

2y(2+y)=(-6)

2+y=(-6)/2y

2+y=-3/y

2=-3/y-y

by solve this

y^2+2y+3

then its roots are y=1and y=-3

By given equation x^3-8y^3

by y=1, then x=8

and by y=-3, then x=-24

I hope that you are satisfied with this answer.

Similar questions