Question

(x+2y+4z)² ,Expand it, using suitable identities.

Answer 1

this answer makes you better understanding

Answer 2

Solution :

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We know the algebraic identity ,

(a+b+c)² = a²+b²+c²+2ab+2bc+2ca

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Now ,

( x + 2y + 4z )²

=x²+(2y)²+(4z)²+2x(2y)+2(2y)(4z)+2(4z)x

= x² + 4y² + 16z² + 4xy + 16yz + 8zx

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