Question

(x+2y+4z)² (x+2y+4z)²​

Answer 1

Answer:

x²-4y²-8z² the answer....... ...

Answer 2

(x+2y+4z)² (x+2y+4z)²​

Solution:

$(x+2y+4z)^2$

using $(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac$

where,

$a=x, b=2y, c=4z$

$=x^2+(2y)^2+(4z)^2+2(x)(2y)+2(2y)(4z)+2(4z)(x)\\=x^2+4y^2+16z^2+4xy+16yz+8xz$

$(x+2y+4z)^2=x^2+4y^2+16z^2+4xy+16yz+8xz$

Explanation:

• we using $(a+b+c)^2$ formula.

• The $(a+b+c)^2$ formula is one of the important algebraic identities.

• The $(a+b+c)^2$ formula is expressed as $a^2+b^2+c^2+2ab+2bc+2ca$.

• where $a=x, b=2y, c=4z$.
• Substitute the values .$a=x, b=2y, c=4z$
• And finally we get the answer.