Math, asked by vishalvishal80506, 17 hours ago

(X+2y+4z)pawer2 using the common identities

Answers

Answered by anuragmandal1245

0

Step-by-step explanation:

We know (a+b+c)²=a²+b²+c²+2ab+2bc+2ca

(x+2y+4z)²

=(x)²+(2y)²+(4z)²+2•x•2y+2•2y•4z+2•4z•x

=x²+4y²+16z²+4xy+16yz+8zx

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