Question

(x-2y-4z) powred 2 solve with identity class 9​

Answer 1

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Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

Method 1 :-

By using the identity -

• $( {a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

$=>( {x - 2y - 4z)}^{2}$

We can write it as →

$( {x + ( - 2y) + ( - 4z))}^{2}$

Use the suitable identity -

${x}^{2} + ( { - 2y)}^{2} + ( { - 4z)}^{2} + 2 \times x \times ( - 2y) + 2 \times ( - 2y) \times ( - 4z) + 2 \times ( - 4z) \times x \\ = {x}^{2} + 4 {y}^{2} + 16 {z}^{2} - 4xy + 16yz - 8zx$

$\rule{200}{1}$

Method 2 :-

By using the identity →

• $( {a - b - c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab + 2bc - 2ca$

$</strong><strong>=</strong><strong>></strong><strong>(</strong><strong> {x - 2y - 4z)}^{2} \\ = {x}^{2} + {(2y)}^{2} + ( {4z)}^{2} - 2 \times x \times 2y + 2 \times 2y \times 4z - 2 \times 4z \times x \\ = {x}^{2} + 4 {y}^{2} + 16 {z}^{2} - 4xy + 16yz - 8xz$

$\rule{200}{1}$

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