X-2y+5=0 orthocentre
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Given lines are 7x + y – 10 = 0 → (1), x – 2y + 5 = 0 → (2), x + y + 2 = 0 → (3) Point of intersection of (2) and (3) is B (–3, 1). Equation of the altitude through B is (x + 3) – 7(y – 1) = 0 ⇒ x – 7y + 10 = 0 → (4) Point of intersection of (3) and (1) is C(2, –4) Equation of the altitude through C is 2(x – 2) + (y + 4) = 0 ⇒ 2x + y = 0 → (5) Solving (4) and (5), orthocenter is (- 2/3, 4/3).Read more on Sarthaks.com - https://www.sarthaks.com/452811/find-the-orthocenter-of-the-triangle-formed-by-the-lines-7x-y-10-0-x-2y-5-0-x-y-2-0?show=452817#a452817
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