Question

x+2y=5,3x/2+3y=10 solve by elimination method

Answer 1

$Given \: x + 2y = 5 \: --(1)$

$and \: \frac{3x}{2} + 3y = 10 \: --(2)$

/* Multiplying equation (1) by 3 and equation (2) by 2 , we get */

$3x + 6y = 15 \:--(3)$

$and \:3x + 6y = 20 \: --- (4)$

Here , Coefficients of x and y are equal .and Constant terms are unequal .

$So, the \:pair \: of \:linear \:equations \; are$

$parallel\: and \: have \:no \: solution.$

•••♪