x+2y=5,3x+ky+15=0. for what value of k does the system of equation?
Answers
Answered by
2
k should have any other value except 6
otherwise they become coincident lines
otherwise they become coincident lines
sumitnagesia:
why???
Answered by
0
Answer:
k=6
Step-by-step explanation:
x+2y=5
3x+ky+15=0
x+2y=5
3x+ky=15
a1/a2=b1/b2
1/3=2/k
k=6
for any value of k the eq have unique solution except 6
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