Question

x-2y=6 ; 3x -6y=0 simultaneousl sum by elimination method.....dont know then dont answer.​

Answer 1

Let x - 2y = 6 ...........eq.(i)

& 3x - 6y = 0 ...........eq.(ii)

Multiplying eq.(i) by 3

So, equation (i) becomes

3x - 6y = 18

Now, 3x - 6y = 18

- 3x - 6y = 0

_____________

-12y = 18

-y = 18/12

y = - 3/2 ........eq.(iii)

Now putting value of y in equation (ii)

3x - 6(-3/2) = 0

3x - (-9) = 0

3x + 9 = 0

3x = -9

x = -3

So, x = -3 & y = -3/2

Answer 2

Answer:-

Given:-

The equations are -

• x - 2y = 6 .........(i)
• 3x - 6y = 0 .........(ii)

To Find:-

The value of x and y by elimination methord.

Solution:-

The equations are -

• x - 2y = 6 ......(i)
• 3x - 6y = 0 .........(ii)

Now, Multiplying eq (i) by 3 and eq. (ii) by 1, we get-

• 3x - 6y = 18
• 3x - 6y = 0

Now, Eliminating both the equations ,

3x - 6y = 18

3x - 6y = 0

(-)....(+).....(-)

0 = 18

So, The above statement is true for any values of x and y .

There is not any true value of x and y .

Therefore, the equation have infinitely many solution and the lines will be colinear .