Question

X=2y+6 then find value of x^3-8y^3-36xy-216

Answer 1

Answer:

X=2y+6

x^3=(2y+6)^3

x^3=8y^3+2.2y.36+2.4y^2.6+216

x^3=8y^3+144y+48y^2+216

now, x^3-8y^3-36xy-216

=8y^3+144y+48y^2+216-8y^3-36xy-216

(putting value of x^3)

=144y+48y^2-36xy

=12(12y+2y^2-3xy)