x+2y=7-------1
x²+y²=10-----2
Pls do it in Elimination Method
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1
x
2
+y
2
−10x−6y+30=0
⇒(x−5)
2
+(y−3)
2
=(2)
2
Centre =(5,3), radius =2
⇒oA=r=2
OB=r=2
from figure,
⇒AC=r=2
⇒BC=r=2
⇒C=(7,1)
Area of OACB=2×2=4
Smallest circle of family s=0 will have AB as diameter.
∴ Centre = mid point of AB=(6,2)
radius =
2
AB
=
2
2
2
=
2
∴ Equation (x−6)
2
+(y−2)
2
=(
2
)
2
⇒x
2
−12x+36+y
2
−4y+4=2
⇒x
2
−12x+y
2
−4y+38=0
Radical axis of family of circles is 4B
equation of AB is
⇒(y−1)=
7−5
8−1
(x−5)
−y−1=x−5
x−y−4=0
I hope it helps you
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