Math, asked by prethalavis, 11 months ago

x+2y=8 and xy=2 find x^2+4y^2

Answers

Answered by CosmicEntity

2

(x+2y)^2=x^2+4y^2+4xy
x^2+4y^2=(x+2y)^2-4xy=64-8=56

Swarup1998: xy = 2

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