Question

x=2y+c and y=4z-d. when x = 0, y = 1 and when y = 8, z = -1. what is the value of 2c + 3d​

Answer 1

x = 2y + c, y = 4z - d

When x = 0, y = 1. That is, 0 = 2(1)+c => c = -2

And, when y = 8, z = -1. That is, 8 = 4(-1)-d => d = -12

Thus, 2c+3d = 2(-2) +3(-12) = -4-36 = -40