x-2y – x² + 4y²
Please solve this
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Step-by-step explanation:
:
\large{ \bold{(x - 2y)(1 - x - 2y)}}(x−2y)(1−x−2y)
Step-by-step explanation:
x - 2y - {x}^{2} + 4 {y}^{2}x−2y−x
2
+4y
2
= x - 2y - ( {x}^{2} - 4 {y}^{2} )=x−2y−(x
2
−4y
2
)
= (x - 2y) - ( {x}^{2} - 2xy + 2xy + 4 {y}^{2} )=(x−2y)−(x
2
−2xy+2xy+4y
2
)
= (x - 2y) - (x(x - 2y) + 2y(x - 2y))=(x−2y)−(x(x−2y)+2y(x−2y))
= (x - 2y) - (x - 2y)(x + 2y)=(x−2y)−(x−2y)(x+2y)
= (x - 2y)(1 - (x + 2y))=(x−2y)(1−(x+2y))
= (x - 2y)(1 - x - 2y)=(x−2y)(1−x−2y)
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