Question

x-2y – x² + 4y²
Please solve this​

Answer 1

Step-by-step explanation:

:

\large{ \bold{(x - 2y)(1 - x - 2y)}}(x−2y)(1−x−2y)

Step-by-step explanation:

x - 2y - {x}^{2} + 4 {y}^{2}x−2y−x

2

+4y

2

= x - 2y - ( {x}^{2} - 4 {y}^{2} )=x−2y−(x

2

−4y

2

)

= (x - 2y) - ( {x}^{2} - 2xy + 2xy + 4 {y}^{2} )=(x−2y)−(x

2

−2xy+2xy+4y

2

)

= (x - 2y) - (x(x - 2y) + 2y(x - 2y))=(x−2y)−(x(x−2y)+2y(x−2y))

= (x - 2y) - (x - 2y)(x + 2y)=(x−2y)−(x−2y)(x+2y)

= (x - 2y)(1 - (x + 2y))=(x−2y)(1−(x+2y))

= (x - 2y)(1 - x - 2y)=(x−2y)(1−x−2y)