X+2y-z=0 ,3x+2y+z=14,4x-2y+3z=11
Answers
Answered by
0
Answer:
+
2
−
=
0
,
3
+
2
+
=
1
4
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4
−
2
+
3
=
1
1
Step-by-step explanation:
x
+
2
−
=
0
,
3
+
2
+
=
1
4
,
4
−
2
+
3
=
1
1
Answered by
1
Answer:
Correct option is
D
x = 1, y = 2, z = 3
let x+2y+3z=14 ------------ (1)
3x+y+2z=11 ---------(2)
2x+3y+z=11 -----------(3)
multiplying eqn (2) by 2 and subtracting eqn(1) from it we get,
=5x+z=8 -------------(4)
again multiplying eqn (2) by 3 and subtracting eqn (3) from it we get,
= 7x+5z=22 ------------(5)
Now multiply eqn (4) by 5 and subtract eqn (5) from it we get
18x=18
∴x=1
substituting the x in eqn (4) we get the value of z as
= 5(1)+z=8
∴z=8−5=3
and substitute x and z in eqn (1) we get
1+2y+3(3)=14
2y=14−1−9=4
∴y=2
hence the answer is option D
Step-by-step explanation:
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