Question

x+2y_z=3 3x_y+2z=1 2x_2y+3z=2 verify the following system of consistency and if constant solve​

Answer 1

Step-by-step explanation:

x + 2y-z=3 Eq1

3x-y + 2z = 1 Eq2 2x-2y + 3z = 2 Eq3 X-y +z = -1 Eq4

Eq2 - Eq3

=> x + y = z = -1 Eq5 -

x + 2y-z = 3 Eq1

Eq1 - Eq5

=> y = 4

Eq1 + Eq4

=> 2x + y = 2 => 2x + 4 = 2

=> x= -1x = -1

y = 4

z = 4

-1+8-4 3

-3-4+8=1

Eq1

Eq2

-2 --8y + 12 = 2 Eq3

-1-4 + 4 = -1

Eq4

All equations satisfies

Hence Equations have at least one solution

x= -1, y = 4, z = 4 I think my answer write