Question

x+2y-z=6,-3y-2y+5z=-12,x-2z=3​

Answer 1

Step-by-step explanation:

x+2y-z = 6_____________________{i}

-3y -2y +5z =-12

» -5y+5z=-12

» 5z= -12+5y

» 5z +12=5y

» (5z+12)/5= y _____________{ii}

x-2z=3

» x=3+2z_________________{iii}

substituting the value of x and y from eq ii and iii

in eq i

» [ 3+2z ] +2[ ( 5z+12 )/ 5 ] -z =6

» 3+2z + (10z+24)/5 -z = 6

» 2z -z + (10z+24)/5 = 6-3

» z + (10z+24)/5 = 3

» 5z/5 + (10z+24)/5= 3

» (5z+10z+24)/5= 3

» 15z +24 =3×5

» 15z= 15 -24

» 15z= -9

» z= -9/15

» z= -3/5

substituting the value of z in eq ii

» [5(-3/5) +12]/5=y

» [-15/5 + 12]/5=y

» [-3 + 12]/5=y

» 9/5=y

substituting the value of z in eq iii

» x=3+2z

» x = 3+ 2(-3/5)

» x= 15/5 + -6/5

» x=(15-6)/5

» x= 9/5

buddy here is your answer