Question

x+2y+z=7 2x+y-3z=-2 x-3Y=2z=-1

Answer 1

Answer:

x=2,y=1,z=3

Step-by-step explanation:

We have,

x+2y+z=7 .(i)

x+3z=11 .(ii)

2x−3y=1 ..(iii)

From equation (i), we get

z=7−x−2y

Substituting z=7−x−2y in equation (ii), we get

x+3(7−x−2y)=11

⇒x+21−3x−6y=11

⇒−2x−6y=−10  ..(iv)

Adding equations (iii) and (iv), we get

−9y=−9⇒y=1

Putting y=1 in equation (iii), we get x=2.

Putting x=2,y=1 in equation (i), we get

2+2+z+7⇒z=3

Hence, x=2,y=1,z=3.