x^3+1=0what is the value of x cube + 1 is equal to zero
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no the answer is -1 because -1*-1*-1
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Hi,
Here's ur answer :-
x^3 +1 = 0
=> (x)^3 + (1)^3 = 0
=> (x+1)(x^2+ 1+x)=0
=> (x+1){(x+1)^2-x+x }
=> (x+1)(x+1)^2 = 0
=> (x+1)(x+1)(x+1) =0
Let x + 1 = 0
=> x = -1
So, x = -1 or -1 or -1
HOPE IT HELPS (^_^)
PLEASE MARK BRAINLIEST
Here's ur answer :-
x^3 +1 = 0
=> (x)^3 + (1)^3 = 0
=> (x+1)(x^2+ 1+x)=0
=> (x+1){(x+1)^2-x+x }
=> (x+1)(x+1)^2 = 0
=> (x+1)(x+1)(x+1) =0
Let x + 1 = 0
=> x = -1
So, x = -1 or -1 or -1
HOPE IT HELPS (^_^)
PLEASE MARK BRAINLIEST
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