Question

x=3^1/4+3^-1/4 and y=3^1/4-3^-1/4,then the value of 3(x^2+^2)^2?​

Answer 1

Answer:

Given,

2

x+y−8

=

3

x+2y−14

=

4

3x−y

By taking first two. we get,

2

x+y−8

=

3

x+2y−14

⇒3x+3y−24=2x+4y−28

⇒x−y=−4 ......(i)

By taking last two. we get,

3

x+2y−14

=

4

3x−y

⇒4x+8y−56=9x−3y

⇒5x−11y=−56 .....(ii)

On multiplying equation (i) by 5. we get,

5x−5y=−20 ....(iii)

On subtracting (ii) from (iii). we get,

5x−5y−(5x−11y)=−20−(−56)

∴6y=36

∴y=6

Substitute y=6 in (i). we get,

x−6=−4

∴x=2

∴x=2,y=6

Answered By Aashish