Question

x + 3 =12
x = 12 -3
.. x = 9
erefore, if both LHS and RHS of an equation are moved (transposed) from o
other side, the values of terms remain same.
Exercise - 2
Solve the following equations without transposing and check your result.
(i)
x + 5 = 9
y - 12 = -5
3x + 4 = 19
(iv) 9z=81
(v)
3x + 8 = 5x + 2
(vi)
5y + 10 = 4y - 10​

Answer 1

(i)x+5=9

x=9-5

x=4

(ii) y - 12 = -5

y= -5+12

y=7

iii) 3x + 4 = 19

3x=19-4

3x=15

x=15/3

x=5

(iv)9z=81

z=81/9

z=9

(v) 3x + 8 = 5x + 2

-2+8 = 5x - 3x

6 = 2x

x=6/2

x=3

(vi) 5y + 10 = 4y - 10

10+10=4y-5y

20= -y

y= -20

I hope my answer helps you☺☺