x^3 - 12x(x - 4) - 63
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Answered by
6
f(x) = x3 - 12x(x-4) - 64
f(x) = x3 - 12x2 + 48x - 64
You want three factors of -64 that add to -12. The answer is -4, -4, -4: (-4)(-4)(-4) = -64, -4 - 4 - 4 = -12. So the factors are:
f(x) = (x-4)(x-4)(x-4) = (x-4)3
To check it, FOIL out the (x-4)3 and verify you get x3 - 12x2 + 48x - 64
f(x) = x3 - 12x2 + 48x - 64
You want three factors of -64 that add to -12. The answer is -4, -4, -4: (-4)(-4)(-4) = -64, -4 - 4 - 4 = -12. So the factors are:
f(x) = (x-4)(x-4)(x-4) = (x-4)3
To check it, FOIL out the (x-4)3 and verify you get x3 - 12x2 + 48x - 64
Answered by
1
Answer:
(x-4)3
Step-by-step explanation:
f(x) = x3 - 12x(x-4) - 64
f(x) = x3 - 12x2 + 48x - 64
You want three factors of -64 that add to -12. The answer is -4, -4, -4: (-4)(-4)(-4) = -64, -4 - 4 - 4 = -12. So the factors are:
f(x) = (x-4)(x-4)(x-4) = (x-4)3
To check it, FOIL out the (x-4)3 and verify you get x3 - 12x2 + 48x - 64
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