Math, asked by dourabh59, 7 months ago

x^3-19x+30 factorize this please help me​

Answers

Answered by dadeechvansh
1

Step-by-step explanation:

x³ - 19x + 30

=x^3-19x+38-8

=x^3-8-19x+38

=(x^3-2^3)-(19x+38)

=(x-2)(x^2+2x+4)-19(x-2)

=[(x-2)(x^2+2x-15)]

=(x-2)(x+5)(x-3)

Answered by rajeevr06
3

Answer:

 {x}^{3}  - 19x + 30 = 0

 {x}^{3}  - 2 {x}^{2}  + 2 {x}^{2}  - 4x - 15x + 30 = 0

 {x}^{2} (x - 2) + 2x(x - 2) - 15(x - 2) = 0

(x - 2)( {x}^{2}  + 2x - 15) = 0

(x - 2)( {x}^{2}  + 5x - 3x - 15) = 0

(x - 2)(x + 5)(x - 3) = 0

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