Math, asked by atishkumar45, 11 months ago

x^3-19x-30 solve the factorisation

Answers

Answered by jaideepindore
0

Answer:

5

-2

-3

Step-by-step explanation:

Answered by adityayadav06050
2

Step-by-step explanation:

x^3+0x^2-19x-30

f(x) = x^3+0x^2-19x-30

suppose its one is x+2

x+2 =0

x = -2

f(-2) = x^3+0x^2-19x-30

= -2^3 0×-2^2 -19×-2 -30

= -8 +38 -30

= 0

hence x+2 is real factor of x^3+0x^2-19x-30

now,

dividing

x+2|x^3+0x^2-19x-30|x^2 -2x -15

+-x^3+-2x^2

-------- --------

0 -2x^2-19x-30

-+2x^2 -+4x

----------- ---------

0 -15x - 30

-+15x -+30

------------------------

0

x^2 -2x -15 is another factor

hence its factors are

(x+5)(x-3)(x+2)

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