Question

x= √3+√2, 1/x=? Please find!! ​

Answer 1

Answer:

$\frac{1}{x} = \sqrt{3} - \sqrt{2}$

Step-by-step explanation:

$x = \sqrt{3} + \sqrt{2} \\ \frac{1}{x} = \frac{1}{ \sqrt{3} + \sqrt{2} } \\ = \frac{1( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2} ) } \\ = \frac{ \sqrt{3} - \sqrt{2} }{ ({ \sqrt{3} })^{2} - ({ \sqrt{2} })^{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ = \frac{ \sqrt{3} - \sqrt{2} }{1} \\ = \sqrt{3} - \sqrt{2} \\ = > \frac{1}{x} = \sqrt{3} - \sqrt{2}$

Answer 2

Step-by-step explanation:

I hope it helpful for you completely free