Question

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x - (3√2+2i) x + 6 √2i=0

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Answer 1

Answer:

99 ..!!

Step-by-step explanation:

x= (√3 + √2) / √3 -√2

y= (√3 - √2 ) / √3+ √2

Required

X^2 + y^2 + x y

Answer is 99..!!!!

hope its correct..!!

Answer 2

$x ^{2} - (3 \sqrt{2} + 2i)x + 6 \sqrt{2} i = 0 \\ = > x ^{2} - 3 \sqrt{2} x - 2ix + 6 \sqrt{2} i = 0 \\ = > x(x - 3 \sqrt{2} ) - 2i(x - 3 \sqrt{2}) = 0 \\ = > (x - 3 \sqrt{2} )(x - 2i) = 0 \\ = > x = 3 \sqrt{2} \: or \: x - 2i = 0 \\ = > x = 2i = > {x}^{2} = - 4 \\ = > {( \frac{x}{2}) }^{2} = - 1 \\ = > { (\frac{x}{2} )}^{4} = { - 1}^{2} \\ = > \frac{x}{2} = \sqrt[4]{1} \\ = > \frac{x}{2} = 1 \\ = > x = 2$