Question

X=(√3+√2)÷(√3-√2) and y=(√3-√2)÷(√3+√2) then find the value of x^2+y^2.

Answer 1

Answer is 98 !!!!! I hope

Answer 2

Hey friend,
Here is the answer you were looking for:
Given,
x = ( √3 + √2 )/ (√3 - √2)

y = ( √3 - √2 )/ ( √3 + √2)

On rationalizing,
we get,
x = 5 + 2√6

y = 5 - 2√6

( explanation in the image given)

x^2 + y^2

= ( 5 + 2√6)^2 + ( 5 - 2√6)^2

= [ (5)^2 + (2√6)^2 + 2 × 5 × 2√6 ] + [ (5)^2 + (2√6)^2 - 2 × 5 × 2√6 ]

= 25 + 24 + 20√6 + 25 + 24 - 20√6

= 49 + 49 + 20√6 - 20√6

= 98

HOPE MY ANSWER WOULD BE HELPFUL TO YOU!!!!
AND IF YOU FOUND IT HELPFUL, THEN PLEASE MARK AS BRAINLIEST.
THANKS...
☺