Question

x= √3+ √2

√3− √2

find the value of x2​

Answer 1

Answer:

x= √3+√2/√3-√2

x²= (√3+√2/√3-√2)²

using

(a-b)²=a²+b²-2ab

(a+b)²=a²+b²+2ab

x²=(√3)²+(√2)²+2(√3)(√2)/ (√3)²+(√2)²-2(√3)(√2)

3+2+2√6/3+2-2√6

5+2√6/5-2√6

Rationalising the denominator

(5+2√6)²/(5-2√6)(5+2√6)

using

(a+b)²=a²+b²+2ab

(a-b)(a+b)= a²-b²

(5)²+(2√6)²+2(5)(2√6) / (5)²-(2√6)²

25+24+20√6 / 25-24

x²=48+20√6