(x+3)^2 + 9(3-x) factorise
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x^2+9+18x+27 -9x
x^2+9x+36
x^2+12x-3x+36
x (x+12) -3 (x-12)
(x-3)(x-12)
x=3 x=12
x^2+9x+36
x^2+12x-3x+36
x (x+12) -3 (x-12)
(x-3)(x-12)
x=3 x=12
gopinathgautham123:
thank you
wlcm
How did 18x come in first line of solution, if you can explain to me please. Shouldn't it be 6x?
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