Question

X = √3 - √2 , find x2 + 1 x2

Answer 1

Step-by-step explanation:

(√3-√2)sq +1×(√3+√2)sq

=3-2√6+2+3-2√6+2

=10-4√6

Answer 2

$x = \sqrt{3} - \sqrt{2} \\ \frac{1}{x} = \frac{1}{ \sqrt{3} - \sqrt{2} } \\ \frac{1}{x} = \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \frac{1}{x} = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ \frac{1}{x} = \sqrt{3} + \sqrt{2} \\ \\ x + \frac{1}{x} = \sqrt{3} - \sqrt{2} + \sqrt{3} + \sqrt{2} \\ x + \frac{1}{x} = 2 \sqrt{3} \\ ( {x + \frac{1}{x} })^{2} = ( {2 \sqrt{3} })^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 12 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 10$