Question

x=√3/2 then √(1+x) +√(1-x) =?​

Answer 1

Answer:

We have  x=3√2  and need the value of  1+x−−−−−√+1−x−−−−−√ .

Note that  3–√/2  is the value of  cos30 . That makes the required expression:

1+cos30−−−−−−−−√+1−cos30−−−−−−−−√  

=2cos2302−−−−−−√+2sin2302−−−−−−√  

=2–√(cos15+sin15)−(1)  

Now, for any value of  A ,  (sinA2+cosA2)2=sin2A2+cos2A2+2sinA2cosA2=1+sinA  

sinA2+cosA2=1+sinA−−−−−−−√  

For  A=30 , we have

cos15+sin15=1+sin30−−−−−−−−√=32−−√−(2)  

Substituting  (2)  in  (1) , the value of the required expression is  2–√×32−−√=3

Step-by-step explanation:

Answer 2

Answer:

✓2

Step-by-step explanation:

x=√3/2

then,√1+x +√1+x

√1+√3/2 +√1-√3/2

√2+√3/2+√2-√3/2

√2+✓3+2-√3/2

√2+2/2

√4/2

√2