Question

( x+3)² +(x-3) ²=58​

Answer 1

Answer:

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(x - a)² + (y - b)² = r²

(x0,y0) = (0,9)

(persamaan garis singgung

(x0-a)(x - a) + (y0 - b)(y - b) = r²

(0+3)(x+3) + (9-2)(y-2) = 58

(3)(x+3) + (7)(y-2) = 58

3x + 9 + 7y - 14 = 58

3x + 7y - 5 = 58

3x + 7y = 63

Answer 2

Answer is √20 with + or - sign.