Question

(x+3)² + (y-3) ²= 0 , Let, a+y=?.. solve it.​

Answer 1

${(x + 3)}^{2} + {(y - 3)}^{2} \\ = {x}^{2} + 9 + 6x + {y}^{2} + 9 - 6y \\ = {x}^{2} + {y}^{2} + 6x - 6y + 18$

Answer 2

Answer:

(X)+(3)²+(y)-(3)²=0

(x+9)+(y-9)=0

(x+9)= - (y+9)

(x+y)=-9-9

(x+y)= -18