Question

x^3-23x^2+142x-120
Can you give proper answer
I say that only Ace and virtuoso give answer more than 3000 words.
Another cannot do anything
Who need to became winner

Answer 1

Answer:

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Step-by-step explanation:

= x^3-23x^2+142x-120

let take (x-1) common on the cubic polynomial

= (x-1) [x^2-22x+142-121.

= (x-1) [x^2-22x+21]

split the middle term 22x

= (x-1)[x^2-21x-1x+21]

= (x-1) [x(x-21)-1(x-21)

= (x-1) (x-21) (x-1)

zeros of polynomial are the values of which.

.

. .(x-1)=0,(x-21)=0,(x-1)=0