Question

x^3 -23x^2 + 142x -120 factorize

Answer 1

Hey!!!..here is ur answer

x^3-23x^2+142x-120

put x=1

=(1)^3-23 (1)^2+142 (1)-120

=1-23+142-120

=0

It means one factor of this polynomial is (x-1)

Now we divided the polynomial by (x-1) to find the other factor

=x^3-23x^2+142x-120/(x-1)

=x^2-22x+120

=x^2-10x-12x+120

=x (x-10)-12 (x-10)

=(x-12)(x-10)

So the factor of x^3-23x^2+142x-120

=(x-1)(x-12)(x-10)

Hope it will help you