Question

x^3 - 23x² + 142x - 12​

Answer 1

Answer:

Question -

$factorise \: \: {x}^{3} - {23x}^{2} + 142x - 120$

Required Solution -

${x}^{3} - {23x}^{2} + 142x - 120$

$= {x}^{3} - {x}^{2} - {22x}^{2} + 22x + 120x - 120$

$= {x}^{2} (x - 1) - 22x(x - 1) + 120(x - 1)$

$= (x - 1)( {x}^{2} - 22x + 120)$

= ( x - 1) [ x ( x - 10) - 12 (x - 10) ]

$= > (x - 1)(x - 10)(x - 12)$

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