Question

(x^3+27y^3)-(x^3-27y^3)
8th standard
plz answer ​

Answer 1

Answer:

We know the identity a

3

−b

3

=(a−b)(a

2

+b

2

+ab)

Using the above identity, the equation 8x

3

−27y

3

can be factorised as follows:

8x

3

−27y

3

=(2x)

3

−(3y)

3

=(2x−3y)[(2x)

2

+(3y)

2

+(2x×3y)]=(2x−3y)(4x

2

+9y

2

+6xy)

Hence, 8x

3

−27y

3

=(2x−3y)(4x

2

+9y

2

+6xy)

Answer 2

x^3+27y^3-x^3;27y^3=0

your answer is 0.