Question

x=3+2root 2,value x²_6x+1
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Answer 1

answer: 0

explanation:

Answer 2

Answer:

x=3+2√2

then value of x²-6x+1

(3+2√2)²-6(3+2√2)+1

applying (a+b)²= a²+b²+2ab

(3)²+(2√2)²+2(3)(2√2)-6×3+-6×2√2+1

9+4×2+12√2 - 18 +12√2+1

9+8 +18 + 1+12√2+12√2

36+24√2

12(3+2√2)

JAI SHREE KRISHNA