(x-3) (2x+1) =(x-1) (x+3) quardic equation
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Answer:
(x-3) (2x+1) =(x-1) (x+3)
x(2x+1)-3(2x+1) = x(x+3)-1(x+3)
2x²+x - 6x - 3 = x² + 3x - x - 3
2x²-5x-3 = x²+2x-3
2x²-x²-5x-2x-3+3=0
x²-7x =0
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0
Answer:
Ans:x=0
Hope it is HelpFull to you
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