Question

(x-3)(2x+1)=x(x+5) solve and these are quadratic equation

Answer 1

(x-3)(2x+1)=x(x+5) =>
$x(2x + 1) - 3(2x + 1 )= {x}^{2} + 5x$
$= > 2 {x}^{2} + x - 6x - 3 = {x}^{2} + 5x$
$= > 2 {x}^{2} - {x}^{2} - 5x - 3 - 5x = 0$
${x}^{2} - 10x - 3 = 0$
=> x=10+√100+12/2 and 10-√100+12/2 =>
x=10+4√7/2 and 10-4√7/2 => x=5+2√7 and 5-2√7